WBBSE Class 10 Maths Mensuration Chapter 2 Right Circular Cylinder Multiple Choice Questions

WBBSE Class 10 Maths Mensuration Chapter 2 Right Circular Cylinder Multiple Choice Questions

Example 1. If the length of radii of two solid right circular cylinders are in the ratio 2 : 3 and their heights are in the ratio 5 : 3, the ratio of their lateral surface is

1. 2: 5
2. 8: 7
3. 10: 9
4. 16: 9

Solution: Let radii of r_1,r₂ units and that of height be h_1,h₂ units respectively.

∴ Required ratio = \(\frac{2 \pi r_1 h_1}{2 \pi r_2 h_2}=\frac{2}{3} \times \frac{5}{3}=10: 9\)

∴ Answer is 3. 10: 9

Example 2. If the length of radii of two solid right circular cylinders are in the ratio 2 : 3 and their height in the ratio 5 : 3, then the ratio of their volume is

1. 27: 20
2. 20: 27
3. 4: 9
4. 9: 4

Solution: Let radii be r_1,r₂ units and that of height be h_1,h₂ units respectively.

Read And Learn Also WBBSE Class 10 Maths Multiple Choice Questions

Required ratio = \(\frac{\pi r_1^2 h_1}{\pi r_2^2 h_2}=\left(\frac{2}{3}\right)^2 \times \frac{5}{3}=\frac{4}{9} \times \frac{5}{3}=20: 27\)

∴ Answer is 2. 20: 27

Class 10 Maths Mensuration Chapter 2 MCQs

Example 3. If volumes of two solid right circular cylinder are same and their height are in the ratio 1: 2, then the ratio of length of radii is

1. 1:√2
2. √2: 1
3. 1: 2
4. 2:1

Solution: Let radii be r_1,r₂ units and that of height h_1,h₂ units.

∴ \(\pi r_1{ }^2 h_1=\pi r_2{ }^2 h_2\)

or, \(\left(\frac{r_1}{r_2}\right)^2=\frac{h_2}{h_1}=\frac{2}{1}\)

∴ r₁: r₂ = √2: 1

∴ Answer is 2. √2: 1

Example 4. In a right circular cylinder, if the length of radius is halved and height is doubled, volume of cylinder will be

1. Equal
2. Double
3. Half
4. 4 times

Solution: volume = πr²h cubic unit

changed volume = \(\pi\left(\frac{r}{2}\right)^2\) .2h cubic unit = \(\frac{\pi r^2 h}{2}\) cubic units

∴ Answer is 3. Half

Example 5. If the length of radius of a right circular cylinder is doubled and height is halved, the lateral surface area will be

1. Equal
2. Double
3. Half
4. 4 times

Solution: Volume πr²h c.u

changed volume = π(2r)².\(\frac{h}{2}\) c.u.= 2πr²h cubic units.

∴ Answer is 2. Double

Example 6. Diameter and height of two solid right circular cylinders are 8 units and 3(h – 1) units respectively and the volumes are equal, then h =?

1. 9
2. 2
3. 17
4. 19

Solution: \(\pi\left(\frac{8}{2}\right)^2 \cdot 3(h-1)=\pi\left(\frac{12}{2}\right)^2 \times(h+5)\)

or, 48 (h – 1) = 36 (h + 1) or, 12h = 228

∴ h = 19

∴ Answer is 4. 19

Wbbse Class 10 Maths Mensuration Notes

Example 7. Volume of a cylindrical tank is 6160 cubic metro and radius is 14 metro. Depth is

1. 8 metre
2. 10 metre
3. 14 metre
4. 16 metre

Solution: π (14)².h = 6160 or, h = \(\frac{6160 \times 7}{22 \times 14 \times 14}\) = 10

∴ Answer is 2. 10 metre

Example 8. No. of coins with diameter 3 cm and 0.25 cm thickness from a cuboid of dimension 11 cm x 9 cm x 6 cm will be

1. 320
2. 330
3. 336
4. 340

Solution: No. of coins = \(\frac{11 \times 9 \times 6}{\frac{22}{7} \times \frac{3}{2} \times \frac{3}{2} \times 0.25}\) = 336

∴ Answer is 3. 336

Class 10 Mensuration Chapter 2 Mcqs With Answers

Example 9. Area of the bane and lateral surface area of a cylinder of radius 8 cm are equal. Height will be

1. 3 cm
2. 4 cm
3. 5 cm
4. 6 cm

Solution: πr² = 2πrh

⇒ h = \(\frac{r}{2}\) = \(\frac{8}{2}\) = 4

∴ Answer is 2. 4 cm

Example 10. Volume of the hollow cylinder of outer radius R, inner radius r and height h will be

1. π (R² + r²)h
2. π (R² – r²)h
3. \(\frac{\pi}{2}\)(R² – r²)h
4. \(\frac{\pi}{2}\)(R² + r²)h

Solution: Answer is 2. π (R² – r²)h