WBBSE Class 10 Maths Trigonometry Chapter 1 Concept Of Measurement Of Angle Multiple Choice Questions
Example 1. The end point of the minute hand of a clock rotates in 1 hour
- \(\frac{\pi^c}{4}\)
- \(\frac{\pi^c}{2}\)
- πc
- 2πc
Solution: The end point of the minute hand of a clock rotates in 1 hour is 360°
Read And Learn Also WBBSE Class 10 Maths Multiple Choice Questions
180° = πc
\(360^{\circ}=\frac{360}{180} \pi^c=2 \pi^c\)∴ The correct answer is 4.

Example 2. \(\frac{\pi}{6}\) radian equal to
- 60°
- 45°
- 90°
- 30°
Solution: \(\frac{\pi}{6}\) radian = \(\frac{180^{\circ}}{6}\) = 30°
∴ The correct answer is 30°
Class 10 Maths Trigonometry Chapter 1 MCQs
Example 3. The circular value of each internal angle of a regular hexagon is
- \(\frac{\pi}{3}\)
- \(\frac{2\pi}{3}\)
- \(\frac{\pi}{6}\)
- \(\frac{\pi}{4}\)
Solution: The value of each internal angle of a regular hexagon is
⇒ \(\frac{2 \times 6-4}{6} \times 90^{\circ}=120^{\circ}\)
⇒ \( 180^{\circ}=\pi^c\)
⇒ \(120^{\circ}=\frac{120}{180} \pi^c=\frac{2 \pi^c}{3}\)
∴ The circular value of each angle is \(\frac{2 \pi^c}{3}\)
∴ The correct answer is 2. \(\frac{2\pi}{3}\)
Example 4. The measurement of θ in the relation to S = rθ is determined by
- Sexagesimal system
- Circular system
- Those two methods
- None of these
Solution: The correct answer is 2. Circular system
Trigonometric Ratios Mcqs Class 10
Example 5. In cyclic quadrilateral ABCD, if ∠A = 120°, then the circular value of ∠C is
- \(\frac{\pi}{3}\)
- \(\frac{\pi}{6}\)
- \(\frac{\pi}{2}\)
- \(\frac{2\pi}{3}\)
Solution: In cyclic quadrilateral ABCD, [The opposite angles of a cyclic quadrilateral are supplementary]
∠A + ∠C = 180°
120° + ∠C = 180°
⇒ ∠C = 60°
180° = πc
∴ 60°= \(\frac{60}{180} \pi^c=\frac{\pi^c}{3}\)
∴ The correct answer is 1. \(\frac{\pi}{3}\)
Class 10 Trigonometry Chapter 1 Mcqs With Answers
Example 6. In ΔABC, point of intersection of ∠B and ∠C is O; if ∠BAC = 40°, then the circular value of ∠BOC is
- \(\frac{5 \pi}{18}\)
- \(\frac{4 \pi}{12}\)
- \(\frac{11 \pi}{18}\)
- \(\frac{2 \pi}{5}\)
Solution:

∠BOC = 90° + \(\frac{1}{2}\) ∠BAC
= 90° + \(\frac{1}{2}\) x 40° = 110°
180° = πc
⇒ 110° = \(\frac{110}{180} \pi^c=\frac{11 \pi^c}{18}\)
∴ The correct answer is 3. \(\frac{11 \pi}{18}\)
Example 7. If ∠A + ∠B = \(\frac{5 \pi}{12}\) and ∠A – ∠B = 15° then the sexagesimal value of ∠B is
- 45°
- 60°
- 75°
- 30°
Solution:

⇒ ∠B = 30°
∴ The correct answer is 4. 30°
Trigonometric Identities Mcqs Class 10
Example 8. If O is the circumcentre of the ΔABC and ∠BOC = 120° then the circular value of ∠BAC is
- \(\frac{\pi}{3}\)
- \(\frac{\pi}{6}\)
- \(\frac{2\pi}{3}\)
- None of these
Solution:

∠BOC = 2 ∠BAC
⇒ ∠BAC = \(\frac{1}{2}\) ∠BOC = \(\frac{1}{2}\) x 120° = 60°
180 = πc
60° = \(\frac{60}{180} \pi^c=\frac{\pi^c}{3}\)
∴ The correct answer is 1. \(\frac{\pi}{3}\)