WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs

Algebra Chapter 7 Graphs

⇒ Graphs are pictorial representations of mathematical data and relations.

⇒ To construct a graph some sort of graph paper is used. The graph paper is divided into small squares.

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⇒ To locate the exact position of a point we need two number lines that are perpendicular to each other, they are called co-ordinate axes.

⇒ The horizontal number line XOX’ is called X-axis and the vertical number line YY’ is called Y axis.

⇒ The point O at which the two axes intersect is called the origin.

 

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs

⇒ The region within angle XOY is called 1st quadrant.

⇒ The region within angle YOX’ is called 2nd quadrant.

⇒ The region within the angle X’OY’ and Y’OX are called 3rd and 4th quadrants respectively.

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⇒ We get the distance from Y-axis is X coordinate and the distance from X-axis is Y.

⇒ The X coordinate is called the abscissa and the Y coordinate is called the ordinate.

⇒ The coordinate of origin O is (0, 0).

⇒ Signs of abscissa and ordinate in the quadrants is shown.

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs

To find out the points (6, 5), (-4, 5), (- 10, -5), (7,-4)

Solution:

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs Signs Of Abscissa And Ordinate In The Quadrant Points (6,5),(4,5),(-10,-5),(7,-4)

1. To plot the point (6,5)

  1. I drew two axis X’OX and YOY’ on the graph paper. The intersection of two axes (0, 0).
  2. From O (0, 0) we moved 6 units to the right side along X-axis, and then from the point we moved 5 units above along the line parallel to Y-axis and reached at the point P its position is (6, 5).

2. To plot the point (-4, 5) from O(0, 0) we moved 4 units to the left side along X-axis, and then from the point we moved 5 units above along the line parallel to Y-axis and reached at the point Q, its position is (-4, 5).

3. To plot the point (- 10, 5) from 0 (0, 0) we moved 10 units to the left side along X-axis, and then from the point we moved 5 units below along the line parallel to Y-axis and reached at the point R, its position is (-10, -5).

4. To plot the point (7,-4) from O(0, 0) we moved 7 units to the right side along X-axis, and then from the point we moved 4 units below along the line parallel to Y-axis and reached at the point S, its position is (-7,-4).

Plot the points (5, 0), (0, 4), (- 3, 0), and (0, -6),

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs Signs Of Abscissa And Ordinate In The Quadrant Points (5,0),(0,4),(-3,0),(-3,0)

1. point A (5, 0) is at 5 unit away from origin (0, 0) on the X-axis.

∴ The distance of point A from the Y-axis is 5 units and from X-axis is 0 unit.

∴ The coordinates of point A is (5, 0).

2. The point B (0, 4) is at 4 unit away from the origin (0, 0) on Y-axis.

The distance of point B from the X-axis is 4 unit and from Y-axis is 0 unit.

∴ The coordinate of point B is (0, 4).

3. The point C (-3, 0) is at 3 unit away from origin on X-unit towards left.

∴ The distance of point C from Y-axis is 3 unit and from X-axis is 0 unit.

∴ The coordinate of C is (-3, 0).

4. The distance of point D from X-axis is 6 unit and from Y-axis is 0 unit.

∴ The coordinate of point D is (0,-6).

Algebra Chapter 7 Graphs Examples:

Example 1. If

  1. Plot points (3, 4), (-6, -1), and (8, 7) on the graph paper and see whether they are collinear.
  2. Put three non-collinear points on the graph paper.
  3. Put three more collinear points other than D the above three collinear points on the graph paper and write their coordinates.

Solution:

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs Plot The Points (3,4),(-6,-1),(8,7) And Prove Collinear

1. The points (3, 4), (-6, -1), and (8, 7) are plotted on the graph paper.

⇒ We join these three points by a straight line AB.

⇒ Hence these three points are collinear.

2. Three non-collinear points (-9, 4), (3, 8), and (12, 3) are plotted on the graph paper.

3. Three more collinear points (- 5, 7), (9, 4), and (11, 8) other than the above three collinear points are plotted and these three points are joint by a straight line CD.

Example 2. See the graph on the graph paper beside and find the answers to the questions below:

1 guava = length of the smallest squares along X-axis and 1 rupee = length of a side of one smallest square along Y-axis.

  1. Write the relation between the number of guava and the price of guava from the graph.
  2. Write the price of 4 guava.
  3. Write the number of guavas in 30 from the graph.
  4. Write the number of guavas in 9.

Solution:

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs 1 Guava Equal To X-axis And 1 Rupee Equal To Y-axis

  1. As the number of guava increases then the price of guava also increases. So the price of guava is proportional to the number of guavas.
  2. The price Price of 4 guavas is 12.
  3. The number of guavas in 30 is 10.
  4. The number of guavas in 9 is 3.

Example 3. Draw the graph on the graph paper of the following data and see whether it is a linear graph. Also, find out the price of 6 books and the number of exercise books for Rs. 100 from the graph.

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs Table For Number Of Books And Price Of Books

Solution:

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs In Graph Paper Number Of Books And Price Of Books

  1. At first drawing X-axis and Y-axis we took a scale along the two axis.
  2. Let’s we consider the length of a side of the smallest square along X-axis = 2 books and length of the side of the smallest square along Y-axis = 5 rupees.
  3. From given data let’s plot (2, 50), (3, 75), (5, 125), (8, 200), and (10, 250) in the graph paper.
  4. Joining the points, we got a straight line, segment PQ. So it is a linear graph.

From the graph, the price of 6 books is 150 and the number of books for 100 is 4.

Example 4. If Draw the graph of y = x + 2.

Solution: y = x + 2

Tabulation:

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs Tablulation For y = x+2

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs In Graph y = x + 2

1 small division on X-axix and Y-axis = 1 unit.

⇒ First, we plot the point A (1, 3), B (3, 5) C (5, 7), then we find A, B, and C which are colinear (PQ).

Example 5. Draw the graph, y = 6.

Solution: y = 6 means for any real value of x, value of y is always 6.

Tabulation:

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs Tabulation y = 6

WBBSE Solutions For Class 8 Maths Algebra Chapter 7 Graphs In Graph In Graph y = 6

Taking 1 small division 1 unit on both the axes we plot P (5, 6), Q (0, 6), R (7, 6) and join P, Q, R which is a linear graph.

Example 6. Choose the correct answer:

1. Value of abscissa of each point on the y-axis is

  1. 0
  2. 1
  3. -1
  4. None of these

Solution: Correct answer is 1. 0

2. Value of the ordinate of each point on the X-axis is

  1. 1
  2. 0
  3. -1
  4. None of these

Solution: Correct answer is 2. 0

3. (2, 3) lies on

  1. 2nd quadrant
  2. 3rd quadrant
  3. 1st quadrant
  4. None of these

Solution: Correct answer is 3. 1st quadrant

Example 7. Write ‘True’ or ‘False’:

1. (-2, 0) lies on the 2nd quadrant.

Solution: The statement is true.

2. A lies on X-axis, its abscissa is always zero.

Solution: The statement is false.

3. A (5, 7) and B (7, 5) are same points.

Solution: The statement is false.

Example 8. Fill in the blanks:

1. (0, 2) lies on the _________ side of Y axis.

Answer: Positive.

2. The line joining (1, 1), (2, 2) passes through _________

Answer: Origin.

3. Position of a point was first thought by _________

Answer: Rene Descartes.

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