WBBSE Solutions For Class 9 Maths Arithmetic Chapter 1 Real Numbers

Arithmetic Chapter 1 Real Numbers

⇔ Natural Numbers: 1, 2, 3, 4, 5,………………… 125, ………….. are counting numbers or natural numbers such that 1 is the first natural number and there is no last natural number.

⇒The natural number is denoted by N and is written as

⇒ N = (1, 2, 3, 4, ……………..,125,………………….).

WBBSE Solutions For Class 9 Maths Arithmetic Chapter 1 Real Numbers

 

⇔ Whole numbers: The numbers 0, 1, 2, 3,……………, 125,……… are called whole numbers.

⇒ The whole numbers is denoted by W and is written as

⇒ W = (0, 1, 2, 3, 125,…..)

⇔ Integers: The numbers……., -4, -3, -2, -1, 0, 1, 2, 3…….are called Integers.

⇒ The integers is denoted by Z and is written as Z = (…….., -3, -2, -1, 0, 1, 2, 3,………..)

WBBSE Solutions For Class 9 Maths

⇒ The integers greater than 0, i.e. 1, 2, 3,……. are called Positive Integers and the integers less than 0, i.e.-1,2,3,….. are called Negative Integers.

⇒ 0 (Zero) is an integer that is neither positive nor negative.

⇔ Rational Numbers: The numbers which can be expressed in the form of \(\frac{p}{q}\) where p and q are integers and q 0 are called Rational Numbers. eg: 6, \(\frac{3}{4}\), 0, \(\frac{5}{6}\) etc.

⇒ [All integers are Rational Numbers.]

⇔ Irrational Numbers: The numbers which can not be expressed in the form of \(\frac{p}{q}\) where p and q are integers and q #0 are called Irrational Numbers. e.g. √3, π etc.

Some important points:

  1. If two rational numbers x and y such that x < y there is a rational number \(\frac{x+y}{2} \text { i.e. } x<\frac{x+y}{2}<y\)
  2. If x and y are two rational numbers and x < y then, n rational numbers between x and y are (x + d), (x + 2d), (x + 3d),….. (x + nd), where d = \(d=\frac{y-x}{n+1}\)
  3. If the rational numbers of the form \(\frac{p}{q}\) be expressed into decimals, it will be terminating decimal numbers, where q has prime factors 2 and 5 only.
  4. If the rational numbers of the form \(\frac{p}{q}\) be expressed into recurring decimals where q has prime factors other than 2 and 5.
  5. If rational numbers are expanded into decimals it will be terminating are recurring and the fraction whose decimal form is terminating or recurring will be rational.

 

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Arithmetic Chapter 1 Real Numbers True Or False

Example 1. The sum of two rational numbers is always rational.

Solution: The statement is true.

⇒ [e.g. [\(\frac{5}{7}\) + \(\frac{2}{3}\) = \(\frac{29}{21}\)]

Example 2. The sum of two irrational numbers is always irrational.

Solution: The statement is false.

⇒ [6.8. (2+√3)+(4-√3)=6]

Example 3. The product of two rational numbers is rational.

Solution: \(\frac{3}{4}\) x \(\frac{5}{6}\) = \(\frac{5}{6}\) [rational number]

∴ The statement is true.

Example 4. The product of two irrational numbers is always rational.

Solution: √3 × √5 = √15 [irrational number]

⇒ (3+√5)(3-√5)=(3)2-(√5)2

= 9 – 54 [rational number]

∴ The statement is false.

Example 5. Each rational number is real number.

Solution: \(\frac{3}{5}\), 0, √9, –\(\frac{4}{7}\) all are real number.

∴ So the statement is true.

Example 6. Each real number is irrational.

Solution: Clearly the statement is False.

 

Arithmetic Chapter 1 Real Numbers Fill In The Blanks

Example 1. The division of two integers is not always ______

Solution: Integer.

Example 2. The value of (2 + √3)(2 – √3) is ______

Solution: 1

(2 + √3)(2 -√3) = 22 – (√3)2 = 4 – 3 = 1

Example 3. The difference between 1 and 0.9 is ________

Solution: 0

1 – 0.9 = 1 – \(\frac{9}{9}\) = 1 – 1 = 0

Example 4. We will get _______ decimal if \(\frac{7}{20}\) are expanded into decimal.

Solution: Terminating.

20 = 22 x 5

20 has no prime factors except 2 and 5.

∴ The decimal form of \(\frac{7}{20}\) will be terminating.

Arithmetic Chapter 1 Real Numbers Short Answer Type Questions

Example 1. Give an example where sum of two irrational numbers is a rational number.

Solution:

  1. √5, -√5 √5 + (-√5) = 0 [rational number]
  2. 7 + √5; 7 – √5 (7 + √5) + (7 – √5) = 14 [rational number]

Example 2. Give an example where subtraction of two irrational number is a rational number.

Solution:

  1. √7, √7 ⇒ √7-√7=0 [rational number]
  2. (5+√3), (2+√3) ⇒ (5+√3)-(2+√3) = 5 + √3 – 2 – √3 = 3 [rational number]

Example 3. Write a rational number between \(\frac{1}{7}\) and \(\frac{2}{7}\)

Solution: A rational number between \(\frac{1}{7}\) and \(\frac{2}{7}\) is \(\frac{\frac{1}{7}+\frac{2}{7}}{2}\) = \(\frac{3}{7 \times 2}=\frac{3}{14}\)

Example 4. Determine a irrational number between \(\frac{1}{7}\) and \(\frac{2}{7}\).

Solution: \(\frac{1}{7}\) = 0.1428571428571……..= 0.142857

⇒ \(\frac{2}{7}\) = 0.285714285714……= 0.285714

⇒ The irrational number lying between \(\frac{1}{7}\) and \(\frac{2}{7}\) will be non-terminating and non-recurring.

∴ One required irrational number is 0.15015001500015………..

Example 5. Express 0.0123 in the form of \(\frac{p}{q}\) where p and q are integers and q ≠ 0.

Solution: 0.0123 = \(\frac{0123-12}{9000}=\frac{111}{9000}=\frac{37}{3000}\)

Example 6. Write four rational numbers between 2 and 3.

Solution: If x and y are two rational numbers and x < y then, n rational numbers between x and y are (x + d), (x + 2d), (x + 3d)………..(x+nd.), where \(d=\frac{y-x}{x+1}\)

⇒ Here, x = 2, y = 3 and n = 4

⇒ d = \(\frac{3-2}{4+1}=\frac{1}{5}\)

∴ The four rational numbers are

⇒ \(\left(2+\frac{1}{5}\right)\left(2+\frac{2}{5}\right)\left(2+\frac{3}{5}\right),\left(2+\frac{4}{5}\right)\)

i.e. \(\frac{11}{5}, \frac{12}{5}, \frac{13}{5} \text { and } \frac{14}{5}\)

Example 7. Write four irrational numbers between \(\frac{2}{3}\) and \(\frac{5}{3}\)

Solution: \(\frac{2}{3}\) = 0·666…………..0.6

⇒ \(\frac{5}{3}\) = 1.666…………. = 1.6

⇒ The irrational number between \(\frac{2}{3}\) and \(\frac{5}{3}\) will be non-terminating and non-recurring.

∴ Four irrational numbers between \(\frac{2}{3}\) and \(\frac{5}{3}\) are 0.707007000700007……….

⇒ 0.72572557255572………, 0.81481448144481…………., 0.93293229322293……….

Example 8. Place the rational numbers on a Number line.

  1. –\(\frac{3}{4}\)
  2. \(\frac{13}{5}\)

Solution:

1.

WBBSE Solutions For Class 9 Maths Arithmetic Chapter 1 Real Numbers Placing The Rational Number On Number Line-1

 

⇒ At first, 9 take OA’ = 1 unit on the left side of the point ‘0’, OA’ is divided into 4 equal parts.

⇒ OR = –\(\frac{3}{4}\) unit.

2.

WBBSE Solutions For Class 9 Maths Arithmetic Chapter 1 Real Numbers Placing The Rational Number On Number Line-2

 

At first, 9 take OA 1 unit on the right side of the point ‘O’,

∴ OB = 2 units and OC = 3 units.

⇒ BC is divided into 5 equal parts BR = \(\frac{3}{5}\) unit.

∴ OR = OB + BR = = (2 + \(\frac{3}{5}\)) units = \(\frac{13}{5}\) units.

Example 9. Write two rational numbers between 0.2101 and 0.2

Solution: 0.2 = 0.2222………..

⇒ The two rational numbers between 0.2101 and 0.2 are 0.211 and 0.212

Example 10. Express each of the following numbers in the form of \(\frac{p}{q}\) where p and q are integers and q 0.

  1. 0.2345
  2. 12.0366

Solution:

  1. 0.2345 = \(\frac{2345-234}{9000}=\frac{2111}{9000}\)
  2. 12.0306 = \(\frac{120306-1203}{9900}=\frac{119103}{9900}=\frac{39701}{3300}\)

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