WBBSE Class 10 Maths Statistics Chapter 1 Mean Median Ogive Mode Multiple Choice Questions

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WBBSE Class 10 Maths Statistics Chapter 1 Mean Median Ogive Mode Multiple Choice Questions

Example 1. The median of a given frequency distribution is found graphically with the help of

  1. Frequency curve
  2. Frequency polygon
  3. Histogram
  4. Ogive

Solution: The correct answer is 4. Ogive

Read And Learn Also WBBSE Class 10 Maths Multiple Choice Questions

Example 2. If the mean of numbers 6, 7, x, 8, y, 14 is 9, then

  1. x + y = 21
  2. x + y = 19
  3. x – y = 21
  4. x – y = 19

Solution: The mean of numbers 6, 7, x, 8, y, and 14 is

⇒  \(\frac{6+7+x+8+y+14}{6}=\frac{35+x+y}{6}\)

According to quéstion, \(\frac{35+x+y}{6}=9\)

∴ The correct answer is 2. x + y = 19

WBBSE Class 10 Maths Statistics Chapter 1 Mean Median Ogive Mode Multiple Choice Questions

Example 3. If 35 is removed from the data 30, 34, 35, 36, 37, 38, 39, 40 then the median increases by

  1. 2
  2. 1.5
  3. 1
  4. 0.5

Solution: Total number of terms of 30, 34, 35, 36, 37, 38, 39, and 40 is 8

Here n = 8 (i.e. n is even)

∴ median = \(\frac{1}{2}\) [(\(\frac{8}{3}\))th term + (\(\frac{1}{2}\) + 1)th term]

= \(\frac{1}{2}\) [4 th term + 5th term]

= \(\frac{36+37}{2}=\frac{73}{2}=36 \cdot 5\)

If 35 is removed from the given data then, n = 7 [i.e. n is odd]

∴ median = \(\frac{7+1}{2}\) th term = 4th term = 37

∴ The median increases by (37 – 36.5) or 0.5

∴ The correct answer is 4. 0.5

Class 10 Statistics Chapter 1 Mcqs With Answers

Example 4. If the mode of data 16, 15, 17, 16, 15, x, 19, 17, 14 is 15, then the value of x is

  1. 15
  2. 16
  3. 17
  4. 19

Solution: In the given data 15 and 17 each occurs 2 times.

As the mode of given data is 15

∴ The value of x is 15

∴ The correct answer is 1. 15

Example 5. If the median of arranging the ascending order of data 8, 9, 12, 17, x + 2, x + 4, 30, 31, 34, 39, is 15 then the value of x is

  1. 22
  2. 21
  3. 20
  4. 24

Solution: In the given data, n = 10 [i.e. n is even]

∴ median = \(\frac{1}{2}\left[\left(\frac{10}{2}\right) \text { th term }+\left(\frac{10}{2}+1\right) \text { th term }\right]\)

= \(\frac{1}{2}[5 \text { th term }+6 \text { th term }]\)

= \(\frac{x+2+x+4}{2}=\frac{2 x+6}{2}=x+3\)

as per question, x + 3 = 24 ⇒ x = 21

∴ The correct answer is 2. 21

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Measures Of Central Tendency Mcqs Class 10

Example 6. Three values of a variable are 12, 6, and 8, and their frequency are (m – 1), m, and (m + 2) respectively, If arithmetic is 8.2 then the value of m is

  1. 2
  2. 3
  3. 4
  4. 5

Solution:

WBBSE Class 10 Maths Statistics Chapter 1 Mean Median Ogive Mode Three values of a variableAnd Frequency

⇒  \({Mean}(\overline{\mathrm{X}})=\frac{\sum f_i x_i}{\sum f_i}=\frac{26 m+4}{3 m+1}\)

⇒  \(\frac{26 m+4}{3 m+1}=8 \cdot 2\)

⇒ 26m + 4 = 24.6 m + 8.2

⇒ 1.4 m = 4.2 ⇒ m = 3

∴ The correct answer is 2. 3

Class 10 Maths Chapter 1 Statistics Solutions

Example 7. If the mode of data 64, 60, 48, x, 43, 48, 43, 34 is 43, then the value of (x + 3) is

  1. 44
  2. 45
  3. 46
  4. 48

Solution: In the given data 43 and 48 each occurs two times.

As mode is 43, So the value of x is 43

∴ The value of (x + 3) is (43 + 3) or 46

∴ The correct answer is 3. 46

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